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10.0619=c^2
We move all terms to the left:
10.0619-(c^2)=0
We add all the numbers together, and all the variables
-1c^2+10.0619=0
a = -1; b = 0; c = +10.0619;
Δ = b2-4ac
Δ = 02-4·(-1)·10.0619
Δ = 40.2476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{40.2476}}{2*-1}=\frac{0-\sqrt{40.2476}}{-2} =-\frac{\sqrt{}}{-2} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{40.2476}}{2*-1}=\frac{0+\sqrt{40.2476}}{-2} =\frac{\sqrt{}}{-2} $
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